document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165267>Question 165267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the proof below. I provided the given and prove. and I answered #s 1 and 4 already, but how do I answer the middle two. I know the second one should be a given also, but how?\r<BR>\n" );
document.write( "\n" );
document.write( "Given: 5(x+4)=40<BR>\n" );
document.write( "Prove: x=4\r<BR>\n" );
document.write( "\n" );
document.write( "Statements:<BR>\n" );
document.write( "1. 5(x+4)=40<BR>\n" );
document.write( "2. ?<BR>\n" );
document.write( "3. ?<BR>\n" );
document.write( "4. x=4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Reasons:<BR>\n" );
document.write( "1.Given<BR>\n" );
document.write( "2. ?<BR>\n" );
document.write( "3. ?<BR>\n" );
document.write( "4. Substitution Property<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121826 by </B><A HREF=/tutors/aboutme.mpl?userid=midwood_trail><B>midwood_trail(310)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=midwood_trail><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is not a geometric proof question.  This is an algebra proof question.\r<BR>\n" );
document.write( "\n" );
document.write( "You were given:\r<BR>\n" );
document.write( "\n" );
document.write( "5(x + 4) = 40\r<BR>\n" );
document.write( "\n" );
document.write( "You now want to remove the parentheses by multiplying 5 by every terms inside the parentheses.\r<BR>\n" );
document.write( "\n" );
document.write( "5(x + 4) becomes 5x + 20\r<BR>\n" );
document.write( "\n" );
document.write( "The reason I was able to find 5x + 20 is called the distributive law or rule.\r<BR>\n" );
document.write( "\n" );
document.write( "We now have this:\r<BR>\n" );
document.write( "\n" );
document.write( "5x + 20 = 40....We now want to subtract 20 from both sides.  This is called the inverse of addition operation.  This is obtained from the subtraction property of equality.  \r<BR>\n" );
document.write( "\n" );
document.write( "5x + 20 = 40\r<BR>\n" );
document.write( "\n" );
document.write( "5x = 40 - 20\r<BR>\n" );
document.write( "\n" );
document.write( "5x = 20\r<BR>\n" );
document.write( "\n" );
document.write( "Here's what your final prove table looks like:\r<BR>\n" );
document.write( "\n" );
document.write( "Given: 5(x + 4)= 40<BR>\n" );
document.write( "Prove: x = 4 \r<BR>\n" );
document.write( "\n" );
document.write( "Statements:\r<BR>\n" );
document.write( "\n" );
document.write( "1. 5(x+4)= 40<BR>\n" );
document.write( "2. 5x + 20 = 40<BR>\n" );
document.write( "3. 5x = 20  <BR>\n" );
document.write( "4. x = 4 \r<BR>\n" );
document.write( "\n" );
document.write( "Reasons:\r<BR>\n" );
document.write( "\n" );
document.write( "1.Given<BR>\n" );
document.write( "2. Distributive law or rule<BR>\n" );
document.write( "3. subtraction property of equality.<BR>\n" );
document.write( "4. Substitution Property\r<BR>\n" );
document.write( "\n" );
document.write( "I hope this helps.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );