document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165257>Question 165257</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 3 feet less than its length. If the perimeter is 22 feet, what is the width? (Pre-Algebra) By Charles P. Mckeague, fifth addition.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121815 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121815\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = length<BR>\n" );
document.write( "then from \"width of a rectangle is 3 feet less than its length\" we have<BR>\n" );
document.write( "x-3 = width<BR>\n" );
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document.write( "Perimeter = 2(length+width)<BR>\n" );
document.write( "22 = 2(x + x-3)<BR>\n" );
document.write( "22 = 2(2x-3)<BR>\n" );
document.write( "22 = 4x-6<BR>\n" );
document.write( "28 = 4x<BR>\n" );
document.write( "7 feet = x (length)<BR>\n" );
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document.write( "width:<BR>\n" );
document.write( "x-3 = 7-3 = 4 feet (width)<BR>\n" );
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