document.write( "Question 165186: 7.)Solve by completeing the square.\r
\n" ); document.write( "\n" ); document.write( "2x^2+x-6=0 \n" ); document.write( "
Algebra.Com's Answer #121809 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
2x^2+x-6=0
\n" ); document.write( "Group terms first:
\n" ); document.write( "(2x^2+x)-6=0
\n" ); document.write( "(2x^2+x) = 6
\n" ); document.write( "2(x^2 + (1/2)x) = 6
\n" ); document.write( "(x^2 + (1/2)x) = 3
\n" ); document.write( "(x^2 + (1/2)x + 1/16) - 1/16 = 3
\n" ); document.write( "(x^2 + (1/2)x + 1/16) = 3 + 1/16
\n" ); document.write( "(x^2 + (1/2)x + 1/16) = 48/16 + 1/16
\n" ); document.write( "(x + 1/4)^2 = 49/16
\n" ); document.write( "Taking the square root of both sides:
\n" ); document.write( "x + 1/4 = (+-)7/4
\n" ); document.write( "x = -1/4 + (+-)7/4
\n" ); document.write( ".
\n" ); document.write( "Two possible solutions then are:
\n" ); document.write( "x = -1/4 + 7/4 = 6/4 = 1.5
\n" ); document.write( "or
\n" ); document.write( "x = -1/4 - 7/4 = -8/4 = -2
\n" ); document.write( " \n" ); document.write( "
\n" );