document.write( "Question 165247: 37.) Show a complete solution to the problem.\r
\n" ); document.write( "\n" ); document.write( "If the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt (13) feet then what are the length and width?
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Algebra.Com's Answer #121806 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If the perimeter of a rectangle is 20 feet and the diagonal is 2 sqrt (13) feet then what are the length and width?
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\n" ); document.write( "2(L+W) = 20
\n" ); document.write( "L^2 + W^2 = (2sqrt(13))^2
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\n" ); document.write( "Simplify:
\n" ); document.write( "L + W = 10
\n" ); document.write( "(10-W)^2 + W^2 = 4*13
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\n" ); document.write( "Solve for W:
\n" ); document.write( "100 - 20W + 2W^2 = 52
\n" ); document.write( "W^2 - 10W + 24 = 0
\n" ); document.write( "(W-4)(W-6) = 0
\n" ); document.write( "Width = 4 feet and Length = 6 feet
\n" ); document.write( "OR
\n" ); document.write( "Width = 6 feet and Length = 4 feet
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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