document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=21436>Question 21436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have been trying for several hours to solve the following:\r<BR>\n" );
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document.write( "(20+sqrt5-x) = (sqrtx+10)\r<BR>\n" );
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document.write( "I have come to an answer of x^2-390x+154025 and x^2+5x+37006.25 but when I have tried to factor both of these, I haven't been able to so I can find out what x is equal to.\r<BR>\n" );
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document.write( "Can you help? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12180 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12180\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (20+sqrt5-x) = (sqrtx+10)...I ASSUME THE PROBLEM IS <BR>\n" );
document.write( "20  +(5-X)^0.5=(X+10)^0.5...IF THIS IS SO IT HAS NO SOLUTION AND DONT BREAK YOUR HEAD ON THAT.BECAUSE X CANNOT BE MORE THAN FIVE OR LESS THAN -10,AS  THEN WE GET IMAGINARY NUMBERS AND IN THAT RANGE OF X BETWEEN -10 AND +5 THERE IS NO SOLUTION WHICH SATISFIES THAT EQN.AT X=5 WE GET LHS =20..AND RHS CANNOT BECOME 20..AT X=-10 RHS IS ZERO AND LHS CANNOT BE ZERO\r<BR>\n" );
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document.write( "IF NOT PLEASE WRITE THE PROBLEM CORRECTLY BY PUTTING APPROPRIATE BRACKETS...FOR.EX.WHETHER  YOU MEAN<BR>\n" );
document.write( "(sqrtx+10)=10+SQRT(X)...OR...SQRT(X+10)..SIMILARLY\r<BR>\n" );
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document.write( "(20+sqrt5-x)=20-5+SQRT(X)...OR....20+SQRT(X-5)<BR>\n" );
document.write( "THEN I SHALL WORK OUT THE PROBLEM </SPAN>\n" );
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