document.write( "Question 165216This question is from textbook
\n" ); document.write( ": log(base5) x - log(base5)(x-2)= log(base5) 4\r
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Algebra.Com's Answer #121774 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%285%2C%28x%29%29-log%285%2C%28x-2%29%29=log%285%2C%284%29%29\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"log%285%2C%28%28x%29%2F%28x-2%29%29%29=log%285%2C%284%29%29\" Combine the logs on the left side using the identity \"log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%29%2F%28x-2%29=4\" Since the bases of the logs on both sides are equal, this means that the arguments of the logs (the stuff inside the logs) are equal\r
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\n" ); document.write( "\n" ); document.write( "\"x=4%28x-2%29\" Multiply both sides by \"x-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=4x-8\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"x-4x=-8\" Subtract \"4x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-3x=-8\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-8%29%2F%28-3%29\" Divide both sides by \"-3\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=8%2F3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=8%2F3\" which approximates to \"x=2.667\". \r
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