document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165126>Question 165126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman id three times as old as her son,and the sum of their ages id 52.find each person's age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121726 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = son's age<BR>\n" );
document.write( "then because \"woman is three times as old as her son\"<BR>\n" );
document.write( "3x = woman's age<BR>\n" );
document.write( ".<BR>\n" );
document.write( "From:\"sum of their ages id 52\" we get<BR>\n" );
document.write( "x + 3x = 52<BR>\n" );
document.write( "4x = 52<BR>\n" );
document.write( "x = 13 years (son's age)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "woman's age:<BR>\n" );
document.write( "3x = 3(13) = 39 years (mother's age)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );