document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165146>Question 165146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter df a standard basketball court is 288ft.find the dimentions of the basketball court if it's length is 44ft.longer than it's width.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121718 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121718\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w = width<BR>\n" );
document.write( "then because \"it's length is 44ft.longer than it's width\"<BR>\n" );
document.write( "w+44 = length<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Perimeter = 2(width + length)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "288 = 2(w + w+44)<BR>\n" );
document.write( "288 = 2(2w+44)<BR>\n" );
document.write( "288 = 4w+88<BR>\n" );
document.write( "200 = 4w<BR>\n" );
document.write( "50 feet = w (width)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "length:<BR>\n" );
document.write( "w+44 = 50+44 = 94 feet (length)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "solution: dimensions are 50 feet by 94 feet  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );