document.write( "Question 165144: find two numbers such that five times the larger plus three times the smaller is 47,and four times the larger minus twice the smaller is 20. \n" ); document.write( "
Algebra.Com's Answer #121715 by orca(409)\"\" \"About 
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Let x and y be the larger and smaller numbers respectively.
\n" ); document.write( "Use the given fact \"five times the larger plus three times the smaller is 47\" to set up an equation:
\n" ); document.write( "5x + 3y = 47 ...................(1)
\n" ); document.write( "Use the given fact \"four times the larger minus twice the smaller is 20\" to set up another equation:
\n" ); document.write( "4x - 2y = 20 ...................(2)
\n" ); document.write( "Multiply both sides of (1) by 2, we have:
\n" ); document.write( "10x + 6y = 94 ............................(3)
\n" ); document.write( "Multiply both sides of (2) by 3, we have:
\n" ); document.write( "12x - 6y = 60 ............................(4)
\n" ); document.write( "Add (3) and (4), we have
\n" ); document.write( "22x = 154
\n" ); document.write( "x = 7
\n" ); document.write( "Substituting x = 7 into (1), we have
\n" ); document.write( "5*7 + 3y = 47
\n" ); document.write( "Solving for y, we have:
\n" ); document.write( "35 + 3y = 47
\n" ); document.write( "3y = 12
\n" ); document.write( "y = 4\r
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