document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165115>Question 165115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman is three times as old as her son,and the sum of their ages id 52.find each person's age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121711 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let w be the woman's age and s the son's.<BR>\n" );
document.write( "w=3s<BR>\n" );
document.write( "w+s=52<BR>\n" );
document.write( ".<BR>\n" );
document.write( "3s+s=52 substitute 3s for w in the 2nd equation.<BR>\n" );
document.write( "4s=52<BR>\n" );
document.write( "s=13<BR>\n" );
document.write( "w=39<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );