document.write( "Question 165103: The length of each side of square A is increased by 100% to make square B. If the length of the side of square B is increased by 50% to make square C, by what percent is the area of Square C greater than the sum of the areas of squares A and B? \n" ); document.write( "
Algebra.Com's Answer #121699 by edjones(8007)\"\" \"About 
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Let x be a side of square a.
\n" ); document.write( "2x is the length of a side of square b.
\n" ); document.write( "3x is the length of a side of square c.
\n" ); document.write( "A[a]=x^2
\n" ); document.write( "A[b]=(2x)^2=4x^2
\n" ); document.write( "A[c]=(3x)^2=9x^2
\n" ); document.write( "9x^2/(x^2+4x^2)
\n" ); document.write( "=9x^2/5x^2
\n" ); document.write( "=9/5
\n" ); document.write( "=1.8
\n" ); document.write( "So, the area of triangle C is 80% greater than the sum of the areas of triangles A and B.
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\n" ); document.write( "Ed\r
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