document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165097>Question 165097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circular flower bed is surrounded by a ring of grass with an Area of 314 square yards. Find the width of the ring of grass.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121688 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121688\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Are you sure that you don't want find the \"radius\" (instead of the \"width\")? Or do you want to find the diameter?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A=pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the area of a circle formula\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=314=3.14%2Ar%5E2 ALIGN=MIDDLE  ALT=\"314=3.14%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=314 ALIGN=MIDDLE  ALT=\"A=314\"   DISABLED_style= \"max-width:90%; height:auto;\" > and replace <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.14 ALIGN=MIDDLE  ALT=\"3.14\"   DISABLED_style= \"max-width:90%; height:auto;\" > (this is an approximation)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=314%2F3.14=r%5E2 ALIGN=MIDDLE  ALT=\"314%2F3.14=r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by 3.14\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=100=r%5E2 ALIGN=MIDDLE  ALT=\"100=r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2=100 ALIGN=MIDDLE  ALT=\"r%5E2=100\"   DISABLED_style= \"max-width:90%; height:auto;\" > Rearrange the equation.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=10 ALIGN=MIDDLE  ALT=\"r=10\"   DISABLED_style= \"max-width:90%; height:auto;\" > Take the square root of both sides (only the positive square root is considered).\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So the radius of the circle is about 10 yards which means that the diameter is about 20 yards (which is twice the radius) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );