document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165099>Question 165099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 88cm. Find the maximum area possible for a rectangle with this perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121681 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 88cm. Find the maximum area possible for a rectangle with this perimeter.<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "L = Length<BR>\n" );
document.write( "W = Width<BR>\n" );
document.write( "perimeter = 2L + 2W = 88<BR>\n" );
document.write( "Area =L*W<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "2L + 2W = 88<BR>\n" );
document.write( "L+W = 44<BR>\n" );
document.write( "L = 44-W<BR>\n" );
document.write( "Substitute into eqn for Area<BR>\n" );
document.write( "A = (44-W)*W<BR>\n" );
document.write( "88 = 44W - W^2<BR>\n" );
document.write( "W^2 - 44W + 88 = 0<BR>\n" );
document.write( "Set the 1st derivative = 0<BR>\n" );
document.write( "2W - 44 = 0<BR>\n" );
document.write( "W = 22<BR>\n" );
document.write( "Maximum area (for a rectangle) is a square.<BR>\n" );
document.write( "Each side is 22 cm<BR>\n" );
document.write( "The area is 22x22 = 484 sq cm\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );