document.write( "Question 165014This question is from textbook
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\n" ); document.write( "Find center and radius of the circle x^2 + y^2 - 10x + 2y + 25 = 0.\r
\n" ); document.write( "\n" ); document.write( "Let me know if the following below is done wrong. help is appreciated.\r
\n" ); document.write( "\n" ); document.write( "x^2 + y^2 - 10x + 2y = -25\r
\n" ); document.write( "\n" ); document.write( "(x^2 - 10x)-(y^2 + 2y)= -25 \r
\n" ); document.write( "\n" ); document.write( "( x^2 -10x -10) -(y^2 + 2y + 1)= -1 - 10 + 1\r
\n" ); document.write( "\n" ); document.write( "(x - 2)^5 -(y + 1)^2 = -10\r
\n" ); document.write( "\n" ); document.write( "The center is (2,-1); the radius is -2.\r
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Algebra.Com's Answer #121667 by Alan3354(69443)\"\" \"About 
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Find center and radius of the circle x^2 + y^2 - 10x + 2y + 25 = 0.
\n" ); document.write( "Let me know if the following below is done wrong. help is appreciated.
\n" ); document.write( "x^2 + y^2 - 10x + 2y = -25
\n" ); document.write( "(x^2 - 10x)-(y^2 + 2y)= -25
\n" ); document.write( "( x^2 -10x -10) -(y^2 + 2y + 1)= -1 - 10 + 1
\n" ); document.write( "(x - 2)^5 -(y + 1)^2 = -10
\n" ); document.write( "The center is (2,-1); the radius is -2.
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\n" ); document.write( "x^2 + y^2 - 10x + 2y = -25
\n" ); document.write( "[x^2 - 10x] + [y^2 + 2y] = -25 (You have a minus sign before y^2)
\n" ); document.write( "[x^2 - 10x + 25] + [y^2 + 2y + 1] = -25 + 25 + 1 (25 completes the square, not 10, and you subtracted from the right side, didn't add)
\n" ); document.write( "(x-5)^2 + (y+1)^2 = 1
\n" ); document.write( "The center is (5,-1) and the radius is 1. (The radius can't be negative.)\r
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