document.write( "Question 164957This question is from textbook Elementary and Intermediate
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document.write( ": 32.)Solve each equation and check for extraneous solutions.\r
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document.write( "(3sqrt(w+1=6)
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Algebra.Com's Answer #121665 by midwood_trail(310)![]() ![]() ![]() You can put this solution on YOUR website! I assume that you meant to type this: \n" ); document.write( "3(sqrt{w + 1}) = 6 \n" ); document.write( "We want to isolate the radical symbol as our first goal. \n" ); document.write( "To do so, divide both sides by 3 as step one. \n" ); document.write( "Doing so, we now have this radical equation: \n" ); document.write( "sqrt{w + 1} = 6/3 \n" ); document.write( "On the right side 6/3 = 2 and so we get this: \n" ); document.write( "sqrt{w + 1} = 2 \n" ); document.write( "To remove the radical symbol, we square both sides. In other words, raise both sides of the equation to the second power. \n" ); document.write( "[sqrt{w + 1}]^2 = 2^2 \n" ); document.write( "w + 1 = 4 \n" ); document.write( "Subtract 1 from both sides. \n" ); document.write( "w = 4 - 1 \n" ); document.write( "w = 3 \n" ); document.write( "WE NOW CHECK. \n" ); document.write( "To check, plug w = 3 in the original question given to you and simplify. \n" ); document.write( "You were given: 3(sqrt{w + 1}) = 6 \n" ); document.write( "Let w = 3 \n" ); document.write( "3(sqrt{3 + 1}) = 6 \n" ); document.write( "3(sqrt{4}) = 6 \n" ); document.write( "3(2) = 6 \n" ); document.write( "6 = 6....It checks! \n" ); document.write( "Final answer: w = 3 \n" ); document.write( " \n" ); document.write( " |