document.write( "Question 165067: I need to factor 27x^3 - 8y^3 using the difference of two cubes method \n" ); document.write( "
Algebra.Com's Answer #121660 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! This site gives you a better insight: \n" ); document.write( "http://www.purplemath.com/modules/specfact2.htm \n" ); document.write( ". \n" ); document.write( "27x^3 - 8y^3 \n" ); document.write( "(3*3*3)x^3 - (2*2*2)y^3 \n" ); document.write( "3^3x^3 - 2^3y^3 \n" ); document.write( "(3x)^3 - (2y)^3 \n" ); document.write( ". \n" ); document.write( "This is a \"special case\" of the \"difference of two cubes\". \n" ); document.write( "a^3 – b^3 = (a – b)(a^2 + ab + b^2) \n" ); document.write( ". \n" ); document.write( "Our 'a' = 3x \n" ); document.write( "and 'b' = 2y \n" ); document.write( ". \n" ); document.write( "Therefore: \n" ); document.write( "27x^3 - 8y^3 = (a – b)(a^2 + ab + b^2) \n" ); document.write( "27x^3 - 8y^3 = (3x – 2y)((3x)^2 + (3x)(2y) + (2y)^2) \n" ); document.write( "27x^3 - 8y^3 = (3x – 2y)(9x^2 + 6xy + 4y^2) \n" ); document.write( " \n" ); document.write( " |