document.write( "Question 165067: I need to factor 27x^3 - 8y^3 using the difference of two cubes method \n" ); document.write( "
Algebra.Com's Answer #121660 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "http://www.purplemath.com/modules/specfact2.htm
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\n" ); document.write( "27x^3 - 8y^3
\n" ); document.write( "(3*3*3)x^3 - (2*2*2)y^3
\n" ); document.write( "3^3x^3 - 2^3y^3
\n" ); document.write( "(3x)^3 - (2y)^3
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\n" ); document.write( "This is a \"special case\" of the \"difference of two cubes\".
\n" ); document.write( "a^3 – b^3 = (a – b)(a^2 + ab + b^2)
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\n" ); document.write( "Our 'a' = 3x
\n" ); document.write( "and 'b' = 2y
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\n" ); document.write( "Therefore:
\n" ); document.write( "27x^3 - 8y^3 = (a – b)(a^2 + ab + b^2)
\n" ); document.write( "27x^3 - 8y^3 = (3x – 2y)((3x)^2 + (3x)(2y) + (2y)^2)
\n" ); document.write( "27x^3 - 8y^3 = (3x – 2y)(9x^2 + 6xy + 4y^2)
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