document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=165047>Question 165047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area of square region having sides of length 6cm is equal to the area of a rectangular region having width 2.5 cms, then the length of the rectangle, in cms is ??????? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121651 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for the area of a rectangle and a square is: Area = (length)(width)<BR>\n" );
document.write( "So, Area (square) = (6cm)(6cm)=36cm because all of the sides of a square are equal.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Since the areas are equal, than:<BR>\n" );
document.write( "A(rectangle)=lw<BR>\n" );
document.write( "36cm=(2.5)(length)<BR>\n" );
document.write( "Solving for \"length\", divide both sides by 2.5cm<BR>\n" );
document.write( "36/2.5=length<BR>\n" );
document.write( "14.4cm=length<BR>\n" );
document.write( "Checking: A(rectangle) = (14.4)(2.5)=36cm<BR>\n" );
document.write( " </SPAN>\n" );
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