document.write( "Question 165051: can someone help\r
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document.write( ". Multiply:
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document.write( "(sqrt[3] + 4sqrt[5])(2sqrt[3] – sqrt[5])\r
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document.write( "and
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document.write( ". Divide:
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document.write( " x2 – 3x + 2/8x - 8 ÷ x2 – 4/5x + 10\r
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Algebra.Com's Answer #121650 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(sqrt[3] + 4sqrt[5])(2sqrt[3] – sqrt[5]) \n" ); document.write( "Applying FOIL: \n" ); document.write( "sqrt[3]2sqrt[3] - sqrt[3]sqrt[5] + 4sqrt[5]2sqrt[3] - 4sqrt[5]sqrt[5] \n" ); document.write( "2(3) - sqrt[15] + 8sqrt[15] - 4(5) \n" ); document.write( "6 - sqrt[15] + 8sqrt[15] - 20 \n" ); document.write( "6 + 7sqrt[15] - 20 \n" ); document.write( "7sqrt[15] - 14 \n" ); document.write( "OR, you could factor: \n" ); document.write( "7(sqrt[15]-2) \n" ); document.write( ". \n" ); document.write( "Divide: \n" ); document.write( "[(x2 – 3x + 2)/(8x - 8)] ÷ [(x2 – 4)/(5x + 10)] \n" ); document.write( "Focusing on the first term in the [], we can factor: \n" ); document.write( "[(x-2)(x-1)/8(x-1)] ÷ [(x2 – 4)/(5x + 10)] \n" ); document.write( "Canceling like-terms: \n" ); document.write( "[(x-2)/8] ÷ [(x2 – 4)/(5x + 10)] \n" ); document.write( ". \n" ); document.write( "Now, focus on the second term in the [], we can factor: \n" ); document.write( "[(x-2)/8] ÷ [(x–2)(x+2)/5(x+2)] \n" ); document.write( "Canceling like-terms: \n" ); document.write( "[(x-2)/8] ÷ [(x–2)/5] \n" ); document.write( ". \n" ); document.write( "Now, we can change the divide to multiplication by flipping one of the terms: \n" ); document.write( "[(x-2)/8] * [5/(x–2)] \n" ); document.write( "Canceling like-terms: \n" ); document.write( "[1/8] * [5/1] \n" ); document.write( "Resulting in: \n" ); document.write( "5/8\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |