document.write( "Question 165032: 1. A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?\r
\n" ); document.write( "\n" ); document.write( "2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?\r
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Algebra.Com's Answer #121638 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
I want to do more than answer it, I want to show you how to do it.
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\n" ); document.write( "A man is now 42 years old and his friend is 33 years old. How many years ago was the man twice as old as his friend was then?
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\n" ); document.write( "Let t = number of yrs for this to be true
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\n" ); document.write( "Subtract t from both sides and make an equation:
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\n" ); document.write( "Man, t yrs ago, was twice as old, as his friend t yrs ago
\n" ); document.write( "42 - t = 2(33 - t)
\n" ); document.write( "42 - t = 66 - 2t; multiply what's inside the brackets
\n" ); document.write( "Some basic algebra operations
\n" ); document.write( "+2t - t = 66 - 42
\n" ); document.write( "t = 24 yrs ago
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\n" ); document.write( "We can prove this
\n" ); document.write( "42 - 24 = 18;
\n" ); document.write( "33 - 24 = 9
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\n" ); document.write( "2. Paul is 3 years younger than his friend Peter. In seven years the product of their ages will be five more than the product of their ages 5 years ago. How old are they now?
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\n" ); document.write( "This problem is impossible, there is no way that the product 7 yrs from now
\n" ); document.write( "will be only 5 more than the product 5 yrs ago\r
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