document.write( "Question 165029This question is from textbook
\n" ); document.write( ": the length of a rectangle is 8 centimeters greater than its width. Find the dimensions of the rectangle if its area is 105 centimeters squared. \n" ); document.write( "

Algebra.Com's Answer #121632 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Remember: $\"A%5BR%5D=LW\"$ , EQN 1
\n" ); document.write( "but, $\"L=8%2BW\"$ , susbt. in EQN 1
\n" ); document.write( " $\"A=%288%2BW%29%28W%29\"$
\n" ); document.write( " $\"105=W%5E2%2B8W\"$
\n" ); document.write( " $\"W%5E2%2B8W-105=0\"$ , perfect square
\n" ); document.write( " $\"%28W%2B15%29%28W-7%29=0\"$
\n" ); document.write( "2 values ---- $\"system%28W=-15cm%2Chighlight%28W=7cm%29%29\"$
\n" ); document.write( "Use $\"W=7cm\"$
\n" ); document.write( "Then, $\"L=8%2B7=15cm\"$
\n" ); document.write( "Check via EQn 1,
\n" ); document.write( " $\"105=15%2A7\"$
\n" ); document.write( " $\"105cm%5E2=105cm%5E2\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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