document.write( "Question 165022: among two supplimentary angles ,the measure of the larger angle is 44 degree more than the measure of the smaller .find the measure. \n" ); document.write( "

Algebra.Com's Answer #121628 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( " $\"A%2BB=180\"$ ,EQN 1----> supplementary angles A & B
\n" ); document.write( "But there's a condition , $\"A=44%2BB\"$ ,larger angle,
\n" ); document.write( "Susbt.in EQN 1,
\n" ); document.write( " $\"44%2BB%2BB=180\"$
\n" ); document.write( " $\"2B=180-44=136\"$
\n" ); document.write( " $\"cross%282%29B%2Fcross%282%29=cross%28136%2968%2Fcross%282%29\"$
\n" ); document.write( " $\"highlight%28B=68%5Eo%29\"$
\n" ); document.write( "Via EQN 1,
\n" ); document.write( " $\"A%2B68=180\"$
\n" ); document.write( " $\"A=180-68\"$
\n" ); document.write( " $\"highlight%28A=112%5Eo%29\"$
\n" ); document.write( "Check via condition:
\n" ); document.write( " $\"A=44%2BB\"$
\n" ); document.write( " $\"112=44%2B68\"$
\n" ); document.write( " $\"112=112\"$
\n" ); document.write( "Via EQN 1: $\"112%2B68=180\"$ , check!
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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