document.write( "Question 23373: 6x-(3-2x)>3x+2 how do you do this?????? \n" ); document.write( "

Algebra.Com's Answer #12161 by rapaljer(4671) $\"\"$ $\"About$

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6x-(3-2x)>3x+2\r
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\n" ); document.write( "\n" ); document.write( "Distribute the -:
\n" ); document.write( "6x - 3 + 2x > 3x +2
\n" ); document.write( "8x - 3 > 3x +2\r
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\n" ); document.write( "\n" ); document.write( "Subtract 3x from each side:
\n" ); document.write( "8x - 3 -3x > 3x +2 -3x
\n" ); document.write( "5x -3 > 2\r
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\n" ); document.write( "\n" ); document.write( "Add +3 to each side:
\n" ); document.write( "5x-3 + 3 > 2+ 3
\n" ); document.write( "5x > 5\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 5:
\n" ); document.write( "x>1\r
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\n" ); document.write( "\n" ); document.write( "Graph on a numberline by going 1 unit to the right, and shade everything to the right of 1, with an arrow on the right end of the numberline, since x>1 means x is any number LARGER than 1, and since it goes forever in the right direction. To indicate that the endpoint at x=1 is NOT included, make an open circle at the point x=1. In higher math, we use an open parentheses on the point x=1, opening to the right.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "

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