document.write( "Question 164980: for the equation a. write the value of the variable that makes a denominator zero:3 over x+2 + 2 over x-2= 8 over (x+2)(x-2) \n" ); document.write( "
Algebra.Com's Answer #121608 by midwood_trail(310) ![]() You can put this solution on YOUR website! If the denominator = 0, then we have a case that is undefined or better said DOES NOT EXIST because we cannot divide by zero.\r \n" ); document.write( "\n" ); document.write( "If we set x + 2 and x - 2 to = 0 and solve for x, we find out that x can be any number except x CANNOT = 2 or -2.\r \n" ); document.write( "\n" ); document.write( "LOOK:\r \n" ); document.write( "\n" ); document.write( "x + 2 = 0\r \n" ); document.write( "\n" ); document.write( "x = -2\r \n" ); document.write( "\n" ); document.write( "=========\r \n" ); document.write( "\n" ); document.write( "x - 2 = 0\r \n" ); document.write( "\n" ); document.write( "x = 2\r \n" ); document.write( "\n" ); document.write( "Final answer: x CANNOT EQUAL -2 or 2 for the expressions given in the denominators because it creates division by zero, which does not exist.\r \n" ); document.write( "\n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |