document.write( "Question 164992: I need to find the vertex for this problem
\n" ); document.write( "f(x)= -3x^+x-5
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Algebra.Com's Answer #121596 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "To find the x-coordinate of the vertex, use this formula: \"x=%28-b%29%2F%282a%29\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-b%29%2F%282a%29\" Start with the given formula.\r
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\n" ); document.write( "\n" ); document.write( "From \"y=-3x%5E2%2Bx-5\", we can see that \"a=-3\", \"b=1\", and \"c=-5\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-%281%29%29%2F%282%28-3%29%29\" Plug in \"a=-3\" and \"b=1\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-1%29%2F%28-6%29\" Multiply 2 and \"-3\" to get \"-6\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F6\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the x-coordinate of the vertex is \"x=1%2F6\". Note: this means that the axis of symmetry is also \"x=1%2F6\".\r
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\n" ); document.write( "\n" ); document.write( "Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3x%5E2%2Bx-5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3%281%2F6%29%5E2%2B1%2F6-5\" Plug in \"x=1%2F6\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=-3%281%2F36%29%2B1%2F6-5\" Square \"1%2F6\" to get \"1%2F36\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=-1%2F12%2B1%2F6-5\" Multiply \"-3\" and \"1%2F36\" to get \"-1%2F12\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=-59%2F12\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the y-coordinate of the vertex is \"y=-59%2F12\".\r
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\n" ); document.write( "\n" ); document.write( "So the vertex is .
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