document.write( "Question 164947This question is from textbook
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document.write( ": Perform the indicated operations and reduce to lowest terms
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document.write( "2/x-3+3/3-x \n" );
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Algebra.Com's Answer #121570 by MRperkins(300)![]() ![]() You can put this solution on YOUR website! I am guessing that you have left out some parenthesis(). If in doubt put parenthesis around nearly everything. I think the problem is supposed to be 2/(x-3)+3/(3-x) which looks like this: \n" ); document.write( "However the problem that you wrote would have looked like this: \n" ); document.write( "\n" ); document.write( "With that said... \n" ); document.write( "in order to add two numbers they must have the same denominator. If we look at the denominators:x-3 and 3-x we notice that one of them is the exact opposite of the other or the negative. So factor out a -1 from 3-x and you get -1(-3+x) which can be written -1(x-3) \n" ); document.write( ". \n" ); document.write( "So now we have \n" ); document.write( ". \n" ); document.write( "Multiply the top and bottom of: \n" ); document.write( "and you get: \n" ); document.write( "Now the whole formula can be written \n" ); document.write( ". \n" ); document.write( "Since the denominators are the same now we can add the two expressions. \n" ); document.write( " \n" ); document.write( "or \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Feedback appreciated \n" ); document.write( "Donations accepted through PayPal @ justin.sheppard.tech@hotmail.com \n" ); document.write( " |