document.write( "Question 164947This question is from textbook
\n" ); document.write( ": Perform the indicated operations and reduce to lowest terms
\n" ); document.write( "2/x-3+3/3-x
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Algebra.Com's Answer #121570 by MRperkins(300)\"\" \"About 
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I am guessing that you have left out some parenthesis(). If in doubt put parenthesis around nearly everything. I think the problem is supposed to be 2/(x-3)+3/(3-x) which looks like this: \"2%2F%28x-3%29%2B3%2F%283-x%29\"
\n" ); document.write( "However the problem that you wrote would have looked like this: \"2%2Fx-3%2B3%2F3-x\"\r
\n" ); document.write( "\n" ); document.write( "With that said...
\n" ); document.write( "in order to add two numbers they must have the same denominator. If we look at the denominators:x-3 and 3-x we notice that one of them is the exact opposite of the other or the negative. So factor out a -1 from 3-x and you get -1(-3+x) which can be written -1(x-3)
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\n" ); document.write( "So now we have \"2%2F%28x-3%29%2B3%2F%28-1%28x-3%29%29\"
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\n" ); document.write( "Multiply the top and bottom of: \"3%2F%28-1%28x-3%29%29\" by -1
\n" ); document.write( "and you get: \"-3%2F%28x-3%29\"
\n" ); document.write( "Now the whole formula can be written \"2%2F%28x-3%29-3%2F%28x-3%29\"
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\n" ); document.write( "Since the denominators are the same now we can add the two expressions.
\n" ); document.write( "\"%282-3%29%2F%28x-3%29\"
\n" ); document.write( "or \"-1%2F%28x-3%29\"
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