document.write( "Question 164944: One number is 12 more than the other. The sum of the smaller number and twice the larger number is 39. Find the larger number. \n" ); document.write( "

Algebra.Com's Answer #121559 by Mathtut(3670) $\"\"$ $\"About$

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lets call our two numbers a and b where a is the smaller and b is the larger. one number is 12 more than the other, so we write this as b=a+12 since b is the larger #. the sum of the smaller a+ twice the larger 2b equals 39 which we would write out as a+2b=39 now taking the a value in the first equation and substituting it into the second equation we get a+2(a+12)=39 which is the same as a+2a+24=39 now combine the a terms and subtract 24 on each side we get 3a=15 therefore a=5 and since b is 12 more than a or b=a+12 we get b=17\r
\n" ); document.write( "\n" ); document.write( "answer small number is 5
\n" ); document.write( " large number is 17 \n" ); document.write( "

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