document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164905>Question 164905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number twice its reciprocal is 3. Find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121538 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  the equation would be as follows: A+2(1/A)=3 where A is the varible we are looking for.  multiply each term by A and we get A^2+2=3A ... now subtract 3A from each side we end up with A^2-3A+2=0  which factors into (A-2)(A-1)=0  setting A-2=0 and A-1=0 we come up with the solution set of  A=1,2  \r<BR>\n" );
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document.write( "answer: 1 and 2 </SPAN>\n" );
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