document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164903>Question 164903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A WIRE 10 IN. LONG IS CUT INTO TWO PIECES. THE TOTAL OF THREE TIMES THE LENGTH OF THE SHORTER PIECE AND ONE IS EQUAL TO THE DIFFERENCE BETWEEN TWICE THE LENGTH OF THE LONGER PIECE AND FOUR. FIND THE LENGHT OF THE LONGER PIECE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121529 by </B><A HREF=/tutors/aboutme.mpl?userid=padmameesala><B>padmameesala(42)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=padmameesala><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A WIRE 10 IN. LONG IS CUT INTO TWO PIECES<BR>\n" );
document.write( "Let x be the length of the shorter piece and y be the length of the longer piece<BR>\n" );
document.write( "Then x+y=10      eqn1<BR>\n" );
document.write( "Given THE TOTAL OF THREE TIMES THE LENGTH OF THE SHORTER PIECE AND ONE IS EQUAL TO THE DIFFERENCE BETWEEN TWICE THE LENGTH OF THE LONGER PIECE AND FOUR<BR>\n" );
document.write( "that is 3x+1=2y-4<BR>\n" );
document.write( "3x-2y=-5       eqn2<BR>\n" );
document.write( "solving the 2 eqns we get<BR>\n" );
document.write( "adding 3x-2y=-5<BR>\n" );
document.write( "and 2x+2y=20<BR>\n" );
document.write( "5x=15<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( "from eqn1 3+y=10<BR>\n" );
document.write( "y=7<BR>\n" );
document.write( "therefore the length of the longer piece is 7inch<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );