document.write( "Question 164817: I have to find the least expensive cost for a steel frame building which measures 600 cu. meters. The prices of horizontal beams are 20d and 30w, vertical beams are 50h. Thank you. \n" ); document.write( "
Algebra.Com's Answer #121505 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The cost equation is
\n" ); document.write( "\"C=20D%2B30W%2B50H\"
\n" ); document.write( "You also know that
\n" ); document.write( "\"V=D%2AW%2AH=600\"
\n" ); document.write( "You can replace one of the variables in the cost equation.
\n" ); document.write( "\"D=600%2F%28WH%29\"
\n" ); document.write( "Then the cost equation becomes,
\n" ); document.write( "\"C=20%28600%2F%28WH%29%29%2B30W%2B50H\"
\n" ); document.write( "\"C=%2812000%29%2F%28WH%29%2B30W%2B50H\"
\n" ); document.write( "\"C=12000W%5E%28-1%29H%5E%28-1%29%2B30W%2B50H\"
\n" ); document.write( "To minimize the cost function we have to find the partial derivative of C with respect to W and H and set those equal to zero.
\n" ); document.write( "1.\"dC%2FdW=12000H%5E%28-1%29%28-W%5E%28-2%29%29%2B30=0\"
\n" ); document.write( "2.\"dC%2FdH=12000W%5E%28-1%29%28-H%5E%28-2%29%29%2B50=0\"
\n" ); document.write( "The understanding is that \"dC%2FdW\" and \"dC%2FdH\" are partial derivatives.
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"12000H%5E%28-1%29%28-W%5E%28-2%29%29%2B30=0\"
\n" ); document.write( "\"12000H%5E%28-1%29%28W%5E%28-2%29%29=30\"
\n" ); document.write( "3.\"HW%5E2=400\"
\n" ); document.write( "From eq. 2,
\n" ); document.write( "\"12000W%5E%28-1%29%28-H%5E%28-2%29%29%2B50=0\"
\n" ); document.write( "\"12000W%5E%28-1%29%28H%5E%28-2%29%29=50\"
\n" ); document.write( "4.\"H%5E2W=240\"
\n" ); document.write( "From eq. 4,
\n" ); document.write( "4.\"H%5E2W=240\"
\n" ); document.write( "\"W=240%2FH%5E2\"
\n" ); document.write( "\"W%5E2=57600%2FH%5E4\"
\n" ); document.write( "Substitute this expression in eq. 3 and solve for H,
\n" ); document.write( "3.\"HW%5E2=400\"
\n" ); document.write( "\"H%2857600%2FH%5E4%29=400\"
\n" ); document.write( "\"57600%2FH%5E3=400\"
\n" ); document.write( "\"H%5E3=57600%2F400=144\"
\n" ); document.write( "\"H=5.24\"
\n" ); document.write( "From eq. 4,
\n" ); document.write( "\"W=240%2FH%5E2\"
\n" ); document.write( "\"W=240%2F%285.24%29%5E2\"
\n" ); document.write( "\"W=240%2F%2827.4576%29\"
\n" ); document.write( "\"W=8.74\"
\n" ); document.write( "Finally,
\n" ); document.write( "\"D=600%2F%28WH%29\"
\n" ); document.write( "\"D=600%2F%285.24%2A8.74%29\"
\n" ); document.write( "\"D=600%2F45.7976\"
\n" ); document.write( "\"D=13.10\"
\n" ); document.write( "The total cost would then be,
\n" ); document.write( "\"C=20%2813.10%29%2B30%2A%288.74%29%2B50%2A%285.24%29\"
\n" ); document.write( "\"C=262%2B262.2%2B262\".... An interesting finding, minimizing cost means each portion makes up exactly 1/3 of the cost.
\n" ); document.write( "\"C=786.2\"
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