document.write( "Question 164862: The perimeter of one square exceeds that of another by 16 and its area is 44 less than 4 times the area of the other. What is the length of the side of each side of each square? \n" ); document.write( "
Algebra.Com's Answer #121498 by gonzo(654)\"\" \"About 
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let p1 = perimeter of one square.
\n" ); document.write( "let p2 = perimeter of the other square.
\n" ); document.write( "let a1 = area of one square.
\n" ); document.write( "let a2 = area of the other square.
\n" ); document.write( "let s1 = side of one square.
\n" ); document.write( "let s2 = side of the other square.
\n" ); document.write( "-----
\n" ); document.write( "p1 = p2 + 16
\n" ); document.write( "-----
\n" ); document.write( "perimeter of a square equals 4 times one side.
\n" ); document.write( "p = 4*s
\n" ); document.write( "-----
\n" ); document.write( "4s1 = 4s2 + 16 (first equation) *****
\n" ); document.write( "s1 = (4s2 + 16)/4
\n" ); document.write( "s1 = s2 + 4
\n" ); document.write( "-----
\n" ); document.write( "a1 = 4a2 - 14
\n" ); document.write( "-----
\n" ); document.write( "area of a square equals one side times the other side (one side squared).
\n" ); document.write( "a = s^2
\n" ); document.write( "-----
\n" ); document.write( "s1^2 = 4(s2^2) - 44 (second equation) *****
\n" ); document.write( "since s1 = s2+4, this equation becomes
\n" ); document.write( "(s2+4)^2 = 4(s2^2) - 44
\n" ); document.write( "to make calculating less confusing, let x = s2
\n" ); document.write( "equation becomes:
\n" ); document.write( "(x+4)^2 = 4x^2 - 44
\n" ); document.write( "this becomes:
\n" ); document.write( "x^2 + 8x + 16 = 4x^2 - 44
\n" ); document.write( "subtract the equation on the left from both sides of the equation and it becomes
\n" ); document.write( "0 = 4x^2 - 44 - x^2 - 8x - 16
\n" ); document.write( "this becomes
\n" ); document.write( "0 = 3x^2 - 8x - 60
\n" ); document.write( "which is the same as
\n" ); document.write( "3x^2 - 8x - 60 = 0
\n" ); document.write( "-----
\n" ); document.write( "that equation factors out to be
\n" ); document.write( "(3x+10)*(x-6) = 0
\n" ); document.write( "factors are:
\n" ); document.write( "x = 6
\n" ); document.write( "or
\n" ); document.write( "x = -10/3
\n" ); document.write( "-----
\n" ); document.write( "since the side of the square can't be negative, the only answer that looks promising is x = 6.
\n" ); document.write( "since x = s2, that means that ...
\n" ); document.write( "s2 = 6.
\n" ); document.write( "-----
\n" ); document.write( "first equation is reproduced here for ease of reference.
\n" ); document.write( "4s1 = 4s2 + 16 (first equation) *****
\n" ); document.write( "since s2 = 6, this equation becomes
\n" ); document.write( "4s1 = 4*6 + 16 = 24 + 16 = 40
\n" ); document.write( "s1 = 10.
\n" ); document.write( "-----
\n" ); document.write( "second equation is reproduced here for ease of reference.
\n" ); document.write( "s1^2 = 4(s2^2) - 44 (second equation) *****
\n" ); document.write( "since s1 = 10, and s2 = 6, this equation becomes
\n" ); document.write( "10^2 = 4*(6^2) - 44
\n" ); document.write( "100 = 4*36 - 44
\n" ); document.write( "100 = 144 - 44
\n" ); document.write( "100 = 100
\n" ); document.write( "s1 and s2 yield correct values for the equations.
\n" ); document.write( "-----
\n" ); document.write( "answer is:
\n" ); document.write( "s1 = 10 = side of one square.
\n" ); document.write( "s2 = 6 = side of the other square.
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