document.write( "Question 164862: The perimeter of one square exceeds that of another by 16 and its area is 44 less than 4 times the area of the other. What is the length of the side of each side of each square? \n" ); document.write( "
Algebra.Com's Answer #121498 by gonzo(654)![]() ![]() ![]() You can put this solution on YOUR website! let p1 = perimeter of one square. \n" ); document.write( "let p2 = perimeter of the other square. \n" ); document.write( "let a1 = area of one square. \n" ); document.write( "let a2 = area of the other square. \n" ); document.write( "let s1 = side of one square. \n" ); document.write( "let s2 = side of the other square. \n" ); document.write( "----- \n" ); document.write( "p1 = p2 + 16 \n" ); document.write( "----- \n" ); document.write( "perimeter of a square equals 4 times one side. \n" ); document.write( "p = 4*s \n" ); document.write( "----- \n" ); document.write( "4s1 = 4s2 + 16 (first equation) ***** \n" ); document.write( "s1 = (4s2 + 16)/4 \n" ); document.write( "s1 = s2 + 4 \n" ); document.write( "----- \n" ); document.write( "a1 = 4a2 - 14 \n" ); document.write( "----- \n" ); document.write( "area of a square equals one side times the other side (one side squared). \n" ); document.write( "a = s^2 \n" ); document.write( "----- \n" ); document.write( "s1^2 = 4(s2^2) - 44 (second equation) ***** \n" ); document.write( "since s1 = s2+4, this equation becomes \n" ); document.write( "(s2+4)^2 = 4(s2^2) - 44 \n" ); document.write( "to make calculating less confusing, let x = s2 \n" ); document.write( "equation becomes: \n" ); document.write( "(x+4)^2 = 4x^2 - 44 \n" ); document.write( "this becomes: \n" ); document.write( "x^2 + 8x + 16 = 4x^2 - 44 \n" ); document.write( "subtract the equation on the left from both sides of the equation and it becomes \n" ); document.write( "0 = 4x^2 - 44 - x^2 - 8x - 16 \n" ); document.write( "this becomes \n" ); document.write( "0 = 3x^2 - 8x - 60 \n" ); document.write( "which is the same as \n" ); document.write( "3x^2 - 8x - 60 = 0 \n" ); document.write( "----- \n" ); document.write( "that equation factors out to be \n" ); document.write( "(3x+10)*(x-6) = 0 \n" ); document.write( "factors are: \n" ); document.write( "x = 6 \n" ); document.write( "or \n" ); document.write( "x = -10/3 \n" ); document.write( "----- \n" ); document.write( "since the side of the square can't be negative, the only answer that looks promising is x = 6. \n" ); document.write( "since x = s2, that means that ... \n" ); document.write( "s2 = 6. \n" ); document.write( "----- \n" ); document.write( "first equation is reproduced here for ease of reference. \n" ); document.write( "4s1 = 4s2 + 16 (first equation) ***** \n" ); document.write( "since s2 = 6, this equation becomes \n" ); document.write( "4s1 = 4*6 + 16 = 24 + 16 = 40 \n" ); document.write( "s1 = 10. \n" ); document.write( "----- \n" ); document.write( "second equation is reproduced here for ease of reference. \n" ); document.write( "s1^2 = 4(s2^2) - 44 (second equation) ***** \n" ); document.write( "since s1 = 10, and s2 = 6, this equation becomes \n" ); document.write( "10^2 = 4*(6^2) - 44 \n" ); document.write( "100 = 4*36 - 44 \n" ); document.write( "100 = 144 - 44 \n" ); document.write( "100 = 100 \n" ); document.write( "s1 and s2 yield correct values for the equations. \n" ); document.write( "----- \n" ); document.write( "answer is: \n" ); document.write( "s1 = 10 = side of one square. \n" ); document.write( "s2 = 6 = side of the other square. \n" ); document.write( "-----\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |