document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164837>Question 164837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1. x^3-4=2, 2. And is this how you solve this problem? x3/2=125, x3/2=5^3 (3/2) 2/3=(5 3/1) 2/3 which the answer is 5^2 or write just 25 as the answer? 3. And how do I solve a algerbracially and check your potential solutions: (x)+20-x=0? 4. And if y=(x)-2 how do I feel in the following table for x=0,1,2? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121475 by </B><A HREF=/tutors/aboutme.mpl?userid=MRperkins><B>MRperkins(300)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MRperkins><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MRperkins><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Good try.  I like to see students at least attempt a problem so thank you for your attempt.  I hope you are able to understand this problem better after my explanation:<BR>\n" );
document.write( "Given:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3-4=2 ALIGN=MIDDLE  ALT=\"x%5E3-4=2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Solve for x:<BR>\n" );
document.write( "Method 1:  add 4 to both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3=6 ALIGN=MIDDLE  ALT=\"x%5E3=6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "take the cubed root of both sides<BR>\n" );
document.write( "x=2\r<BR>\n" );
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document.write( "Method 2:  subtract 2 from both sides<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E3-6=0 ALIGN=MIDDLE  ALT=\"x%5E3-6=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "factor this problem using the special rule for the difference of two perfect cubes which says:\"<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E3-b%5E3=%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29 ALIGN=MIDDLE  ALT=\"a%5E3-b%5E3=%28a-b%29%28a%5E2%2Bab%2Bb%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-2%29%28x%5E2%2B2x%2B4%29 ALIGN=MIDDLE  ALT=\"%28x-2%29%28x%5E2%2B2x%2B4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2%2B2x%2B4%29 ALIGN=MIDDLE  ALT=\"x%5E2%2B2x%2B4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > can further be factored to (x+2)(x+2)<BR>\n" );
document.write( "so<BR>\n" );
document.write( "x^3-6 when factored equals:(x-2)(x+2)(x+2)<BR>\n" );
document.write( "so<BR>\n" );
document.write( "set each set equal to 0<BR>\n" );
document.write( "x-2=0; x+2=0<BR>\n" );
document.write( "so<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%2B-2 ALIGN=MIDDLE  ALT=\"x=%2B-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Check your answers by substituting 2 for x: 2^3 is 2*2*2 or 6;6-4 is 2 and 2=2 is true.<BR>\n" );
document.write( "now check -2.  (-2)^3 =-2*-2*-2 or -8; -8-4 is -12;  -12 does not equal 2 so it is not an answer.  Therefore your only answer is x=2.\r<BR>\n" );
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document.write( "Part 3 of your question does not make sense: (x)+20-x=0<BR>\n" );
document.write( "if you combine like terms then you get 20=0 which is not true.  I think I may have answered what you need in Part 1 of my answer.<BR>\n" );
document.write( "Part 4<BR>\n" );
document.write( "The question is asking you to make a chart of y values when x =0 x=1 and x=2.<BR>\n" );
document.write( "So in the equation y=x-2<BR>\n" );
document.write( "x:y<BR>\n" );
document.write( "0:-2 when x=0 y=-2<BR>\n" );
document.write( "1:-1 when x=1 y=-1<BR>\n" );
document.write( "2:0  when x=2 y=0\r<BR>\n" );
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document.write( "I hope this helps\r<BR>\n" );
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document.write( ".<BR>\n" );
document.write( "Paypal donations accepted through justin.sheppard.tech@hotmail.com\r<BR>\n" );
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document.write( " </SPAN>\n" );
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