document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164843>Question 164843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of the rectangle is one-fourth of its length. if the perimeter is 40 cm. find the dimensions of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121469 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=2L+2W or 2(L+W)   so if W=1/4L and P=40 then lets substitute the knowns into our equation    40=2(L+1/4L)  solving for L we get 2.5L=40 so L=16 and W=1/4(16)<BR>\n" );
document.write( "resulting in W=4\r<BR>\n" );
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document.write( "answer: Length = 16<BR>\n" );
document.write( "        Width  =  4 </SPAN>\n" );
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