document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164841>Question 164841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the difference between the ages of two students is 4 years. if the sum of their ages is 425 years. find each students age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121468 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> students a and b.  so a-b=4 and a+b=425   solve for a in first equation and you get a=b+4  substitute that into 2nd equation  we get (b+4)+b=425  solve for b  b= 210.5 so a =214.5......now that is some old students   were these bible time students????  lol </SPAN>\n" );
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