document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164831>Question 164831</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat travels due East for a distance of 15 miles. It then travels due North for a distance 0f 20 miles, at which point it drops anchor. How many miles is the boat from its starting point? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121454 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A boat travels due East for a distance of 15 miles. It then travels due North for a distance 0f 20 miles, at which point it drops anchor. How many miles is the boat from its starting point?<BR>\n" );
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document.write( "Draw the picture and use Pythagoras to find the distance:<BR>\n" );
document.write( "d = sqrt(15^2 + 20^2) <BR>\n" );
document.write( "d = sqrt(625) = 25 miles<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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