document.write( "Question 162827: how would you graph
\n" ); document.write( "x+5=10
\n" ); document.write( "3x+4y<12
\n" ); document.write( "x+2y=4
\n" ); document.write( "y>-3, x>6
\n" ); document.write( "y=8/3+4
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Algebra.Com's Answer #121443 by Alan3354(69443)\"\" \"About 
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how would you graph
\n" ); document.write( "x+5=10
\n" ); document.write( "3x+4y<12
\n" ); document.write( "x+2y=4
\n" ); document.write( "y>-3, x>6
\n" ); document.write( "y=8/3+4
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\n" ); document.write( "These are all 1st order equations (2 are inequalities), which means the graphs are linear, a straight line. All you need is 2 points, then draw a straight line thru them.
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\n" ); document.write( "x+5 = 10
\n" ); document.write( "x = 5
\n" ); document.write( "No matter what the value of y, x is 5. Pick 2 points, say (5,0) and (5,5). Then draw a straight line thru them. It will be parallel to the y-axis.
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\n" ); document.write( "x+2y = 4
\n" ); document.write( "Find 2 points. The easiest way is to set x = 0 and solve for y, the set y = 0 and solve for x.
\n" ); document.write( "0 + 2y = 4
\n" ); document.write( "y = 2, so the point is (0,2)
\n" ); document.write( "x +2*0 = 4
\n" ); document.write( "x = 4, so the point is (4,0)
\n" ); document.write( "Connect them with a straight line.
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\n" ); document.write( "y=8/3+4
\n" ); document.write( "y = 8/3 + 12/3
\n" ); document.write( "y = 20/3
\n" ); document.write( "Regardless of the value of x, y = 20/3
\n" ); document.write( "This is a line parallel to the x-axis 20/3 units above it.
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\n" ); document.write( "3x+4y<12
\n" ); document.write( "To graph an inequality, solve for the 2 points with an equal sign first.
\n" ); document.write( "Find 2 points. The easiest way is to set x = 0 and solve for y, the set y = 0 and solve for x.
\n" ); document.write( "3*0 + 4y = 12
\n" ); document.write( "y = 3, so the point is (0,3)
\n" ); document.write( "3x + 4*0 = 12
\n" ); document.write( "x = 3, so the point is (3,0)
\n" ); document.write( "Connect the 2 points with a straight line. This is a line with a slope of -1, that is, y is decreasing as x increases.
\n" ); document.write( "The area \"below\" the line is the area where 3x+4y is less than 12. The line is where it is equal, and above it it is greater than.
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\n" ); document.write( "y>-3, x>6
\n" ); document.write( "Locate the point (6,-3). The area above and to the right of the point satisfies the 2 conditions.\r
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