document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164778>Question 164778</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars leave from merrillville indiana at the same time and travel in the same direction one car travels  one and three quater times as fast as the other after 3.5 hours they are 105 miles apart what is the speed of each car </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121425 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.5(1.75x-x)=105<BR>\n" );
document.write( "3.5*.75x=105<BR>\n" );
document.write( "2.625x=105<BR>\n" );
document.write( "x=105/2.625<BR>\n" );
document.write( "x=40 mph for the slow car<BR>\n" );
document.write( "40*1.75=70 mph for the faster car.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "3.5(1.75*40-40)=105<BR>\n" );
document.write( "3.5(70-40)=105<BR>\n" );
document.write( "3.5*30=105<BR>\n" );
document.write( "105=105<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );