document.write( "Question 164734: 4x - 3y = 10
\n" ); document.write( "y - 20 = -6x\r
\n" ); document.write( "\n" ); document.write( "Solve by addition method \n" ); document.write( "
Algebra.Com's Answer #121399 by checkley77(12844)\"\" \"About 
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4x - 3y = 10
\n" ); document.write( "y - 20 = -6x multiply this equation by 3 & add
\n" ); document.write( "3y-60=-18x
\n" ); document.write( "-3y-10=-4x now add.
\n" ); document.write( "------------------------------
\n" ); document.write( "-70=-22x
\n" ); document.write( "x=-70/-22
\n" ); document.write( "x=35/11 answer.
\n" ); document.write( "y-20=-6*35/11
\n" ); document.write( "y-20=-210/11
\n" ); document.write( "y=-210/11+20
\n" ); document.write( "y=(-210+20*11)/11
\n" ); document.write( "y=(-210+220)/11
\n" ); document.write( "y=10/11 answer.
\n" ); document.write( "Proof:
\n" ); document.write( "4*35/11-3*10/11=10
\n" ); document.write( "140/11-30/11=10
\n" ); document.write( "110/11=10
\n" ); document.write( "10=10\r
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