document.write( "Question 164686: The problem is - In 1902, 44 loaves of bread cost the same amount as 1 loaf of bread in 2006. If a loaf of bread in 2006 costs 1.72 more than in 1902, find the cost of a loaf of bread in 1902.\r
\n" ); document.write( "\n" ); document.write( "This is how I did the problem - but I don't think it is right.\r
\n" ); document.write( "\n" ); document.write( "44/1 = x/1.72 \n" ); document.write( "
Algebra.Com's Answer #121395 by ankor@dixie-net.com(22740)\"\" \"About 
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The problem is - In 1902, 44 loaves of bread cost the same amount as 1 loaf of bread in 2006. If a loaf of bread in 2006 costs 1.72 more than in 1902, find the cost of a loaf of bread in 1902.
\n" ); document.write( "This is how I did the problem - but I don't think it is right.
\n" ); document.write( "44/1 = x/1.72
\n" ); document.write( "You're almost right
\n" ); document.write( "\"1%2F44\" = \"x%2F1.72\"; 1.72 buys 44 loaves
\n" ); document.write( "Cross multiply
\n" ); document.write( "44x = 1.72
\n" ); document.write( "x = \"1.72%2F44\"
\n" ); document.write( "x = .039 ~ 4 cents per loaf
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "Check it; .04 * 44 = 1.76 ~ 1.72 \n" ); document.write( "
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