document.write( "Question 164622: Applications of Linear Equations\r
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document.write( "Walt made an extra $9000 last year from a part-time job. He invested part of the money at 9% and the rest at 8%. He made a total of $770 in interest. How much was invested at 8%? \n" );
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Algebra.Com's Answer #121382 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .09x+.08(9000-x)=770 \n" ); document.write( ".09x+720-.08x=770 \n" ); document.write( ".01x=770-720 \n" ); document.write( ".01x=50 \n" ); document.write( "x=50/.01 \n" ); document.write( "x=$5,000 Invested @ 9%. \n" ); document.write( "9000-5000=$4,000 invested @ 8% \n" ); document.write( "Proof: \n" ); document.write( ".09*5000+.08*4000=770 \n" ); document.write( "450+320=770 \n" ); document.write( "770=770 \n" ); document.write( " \n" ); document.write( " |