document.write( "Question 23363: The distance from cambridge to ottawa is 480 jm. Gerry is able to drive at 100 km/h on Highway 401 but can only average 60 k/h on Highway 7. If the trip takes 6 h, how far did he travel on Highway 401.\r
\n" ); document.write( "\n" ); document.write( "Could you solve this please with systems.
\n" ); document.write( "

Algebra.Com's Answer #12138 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Try this:\r
\n" ); document.write( "\n" ); document.write( "\"d1+=+r1t1\" This is the distance traveled on hwy 401 where r1 is 100 km/h
\n" ); document.write( "\"d2+=+r2t2\" This is the distance traveled on hwy 7 where r2 is 60 km/h\r
\n" ); document.write( "\n" ); document.write( "The total distance is d1 + d1 = 480 km.
\n" ); document.write( "The total time is t1 + t2 = 6 hours. Rewrite this as: t2 = 6-t1 \r
\n" ); document.write( "\n" ); document.write( "\"d1+=+100%28t1%29\"
\n" ); document.write( "\"d2+=+60%286-t1%29\" Here, you have substituted for (6-t1) for t2\r
\n" ); document.write( "\n" ); document.write( "\"d1+%2B+d2+=+480\" so:
\n" ); document.write( "\"100%28t1%29+%2B+60%286-t1%29+=+480\" Simplify and solve for t1
\n" ); document.write( "\"100t1+%2B+360+-+60t1+=+480\" Collect like-terms.
\n" ); document.write( "\"40t1+%2B+360+=+480\" Subtract 360 from both sides.
\n" ); document.write( "\"40t1+=+120\" Divide both sides by 40.
\n" ); document.write( "\"t1+=+3\"hours.\r
\n" ); document.write( "\n" ); document.write( "Now you can find d1, the distance traveled on hwy 401.\r
\n" ); document.write( "\n" ); document.write( "\"d1+=+100%28t1%29\"
\n" ); document.write( "\"d1+=+100%283%29\"
\n" ); document.write( "\"d1+=+300\"Km. The distance traveled on hwy 401.
\n" ); document.write( "
\n" );