document.write( "Question 164701: The length of a rectangle is 8 in more than twice its width. If the perimeter of the rectangle is 34 in, find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #121369 by checkley77(12844)\"\" \"About 
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L=2W+8
\n" ); document.write( "2(2W+8)+2W=34
\n" ); document.write( "4W+16+2W=34
\n" ); document.write( "6W=34-16
\n" ); document.write( "6W=18
\n" ); document.write( "W=18/6
\n" ); document.write( "W=3 FOR THE WIDTH.
\n" ); document.write( "L=2*3+8=6+8=14 FOF THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*3+2*14=34
\n" ); document.write( "6+28=34
\n" ); document.write( "34=34
\n" ); document.write( "
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