document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164695>Question 164695</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sorry I made a mistake when I typed it in:\r<BR>\n" );
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document.write( "(4^-2 x y^-3/x^-3 y)^3 times (8^-1 x^-2 y/x^4 y^-1)^-2 = answer x^24/64y^16  - I cannot figure out how to get the 64 in the answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121366 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121366\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when you cube the 1st term out you get (4^-6*x^3*y^-9/x^-9*y^3)  the second term invert and square you get (x^8*y^-2/8^-2*x^-4*y^2)  when you switch 8^-2 to the numerator you have 8^2 or 8squared and when you switch 4^-6 to the denominator you get 4^6 or 4*4*4*4*4*4  when you simplify 8^2/4^6 you get 1/64....that is where the 64 comes into play in the answer....  </SPAN>\n" );
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