document.write( "Question 164688This question is from textbook Statistcal techniques in business and economics
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document.write( ": In establishing warranties on HDTV sets, the manufacturer wants to set the limits so that few will need repair at manufacturer expense.For a new HDTV the mean number of months until repairs are needed is 36.84 with a standard deviation of 3.34 months.Where should the warranty limits be set so that only 10 percent of the HDTVs need repairs at the manufacturer's expense?
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Algebra.Com's Answer #121364 by gonzo(654) ![]() You can put this solution on YOUR website! you want to find the area under the curve of the normal distribution where 10% of the failures lie before and 90% of the failures lie after. \n" ); document.write( "----- \n" ); document.write( "that point is at 32.55962 months. \n" ); document.write( "a warranty that stops there will require you to service 10% of the tv's that are sold. \n" ); document.write( "90% of the tv's that are sold will experience a failure after that number of months. \n" ); document.write( "----- \n" ); document.write( "you can see this in operation by going to the following url: \n" ); document.write( "http://onlinestatbook.com/java/normalshade.html \n" ); document.write( "----- \n" ); document.write( "once you get there, you put in the mean of 36.84 and the standard deviation of 3.34 \n" ); document.write( "you then set your shaded area to be at .1 and you select below: \n" ); document.write( "it should tell you that below 32.5596 is the number you are looking for. \n" ); document.write( "the shaded area under the curve represents 10% of the failures that are expected to occur and this occurs before 32.5596 months have passed. \n" ); document.write( "----- \n" ); document.write( "if you set your shaded area to be at .9 and you select above, you should see where 90% of the failures are expected to lie and this will be after 32.5596 months. \n" ); document.write( " |