document.write( "Question 164621: This question is for Applications of Linear Equations.
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document.write( "Joe has a collection of nickels and dimes that is worth $5.65. If the number of dimes were doubled and the number of nickels were increased by 8,the value of the coins would be $10.45. How many dimes does he have? \n" );
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Algebra.Com's Answer #121341 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Joe has a collection of nickels and dimes that is worth $5.65. If the number of \n" ); document.write( " dimes were doubled and the number of nickels were increased by 8,the value of \n" ); document.write( " the coins would be $10.45. How many dimes does he have? \n" ); document.write( ": \n" ); document.write( "n = no. of dimes \n" ); document.write( "d = no. of nickels \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "\"Joe has a collection of nickels and dimes that is worth $5.65.\" \n" ); document.write( ".05n + .10d = 5.65 \n" ); document.write( "; \n" ); document.write( "\"If the number of dimes were doubled and the number of nickels were increased by 8,the value of the coins would be $10.45.\" \n" ); document.write( ".05(n+8) + .10(2d) = 10.45 \n" ); document.write( ".05n + .40 + .20d = 10.45 \n" ); document.write( ".05n + .20d = 10.45 - .40 \n" ); document.write( ".05n + .20d = 10.05 \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 2, subtract the above equation from it: \n" ); document.write( ".10n + .20d = 11.30 \n" ); document.write( ".05n + .20d = 10.05 \n" ); document.write( "---------------------subtraction eliminates d \n" ); document.write( ".05n = 1.25 \n" ); document.write( "n = \n" ); document.write( "n = 25 nickels \n" ); document.write( ": \n" ); document.write( "How many dimes does he have? \n" ); document.write( ": \n" ); document.write( "Use the 1st equation to find d, substitute 25 for n \n" ); document.write( ".05(25) + .10d = 5.65 \n" ); document.write( "1.25 + .10d = 5.65 \n" ); document.write( ".10d = 5.65 - 1.25 \n" ); document.write( ".10d = 4.40 \n" ); document.write( "d = \n" ); document.write( "d = 44 dimes \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "Confirm our solutions, using the 2nd statement: 33 nickels and 88 dimes \n" ); document.write( ".05(33) + .10(88) = 10.45 \n" ); document.write( "1.65 + 8.80 = 10.45 \n" ); document.write( " |