document.write( "Question 164559: solve for the zeros or roots of this polynomial equation\r
\n" ); document.write( "\n" ); document.write( "k(x)= x-(1/x)\r
\n" ); document.write( "\n" ); document.write( "Please Please explain step by step because I really want to learn how to solve for the zeros of polynomial equations. Thank you for any help. Please Help Soon!
\n" ); document.write( "

Algebra.Com's Answer #121335 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
solve for the zeros or roots of this polynomial equation\r
\n" ); document.write( "\n" ); document.write( "k(x) = x-(1/x)
\n" ); document.write( ":
\n" ); document.write( "Make the equation = to 0
\n" ); document.write( "x - \"1%2Fx\" = 0
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by x to get rid of the denominator
\n" ); document.write( "x*x - x*\"1%2Fx\" = x*0
\n" ); document.write( ":
\n" ); document.write( "results
\n" ); document.write( "x^2 - 1 = 0
\n" ); document.write( ";
\n" ); document.write( "Recognize this as the \"difference of square\" and can be factored to:
\n" ); document.write( "(x+1)*(x-1) = 0; (FOIL this and you will see it)
\n" ); document.write( ":
\n" ); document.write( "Two solutions
\n" ); document.write( "x = -1
\n" ); document.write( "and
\n" ); document.write( "x = +1
\n" ); document.write( ";
\n" ); document.write( ";
\n" ); document.write( "Prove it to yourself. Substitute -1 for x in the original equation
\n" ); document.write( "-1 - \"1%2F%28-1%29\" = 0
\n" ); document.write( "-1 - (-1) = 0
\n" ); document.write( "Which is
\n" ); document.write( " -1 + 1 = 0
\n" ); document.write( ":
\n" ); document.write( "Do the same with x=+1
\n" ); document.write( "
\n" );