document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=23360>Question 23360</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the best solution for 2.3^x = 48 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #12132 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=12132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Do you know about logarithms?  That is the best way!  Take the ln of both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.3%5Ex+=+48 ALIGN=MIDDLE  ALT=\"2.3%5Ex+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%282.3%5Ex%29+=+ln%2848%29 ALIGN=MIDDLE  ALT=\"ln%282.3%5Ex%29+=+ln%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Use the property of logarithms that says  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log+M%5EN+=+N+log+M+ ALIGN=MIDDLE  ALT=\"log+M%5EN+=+N+log+M+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln%282.3%5Ex%29+=+ln%2848%29 ALIGN=MIDDLE  ALT=\"ln%282.3%5Ex%29+=+ln%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A+ln%282.3%29+=+ln%2848%29 ALIGN=MIDDLE  ALT=\"x%2A+ln%282.3%29+=+ln%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now divide both sides of the equation by ln(2.3):\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2A+ln%282.3%29+=+ln%2848%29 ALIGN=MIDDLE  ALT=\"x%2A+ln%282.3%29+=+ln%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2A+ln%282.3%29%29%2F%28ln2.3%29+=+ln%2848%29%2F%28ln2.3%29 ALIGN=MIDDLE  ALT=\"%28x%2A+ln%282.3%29%29%2F%28ln2.3%29+=+ln%2848%29%2F%28ln2.3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "With a calculator, this is \r<BR>\n" );
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document.write( "x= 4.647807191 (approximately) which rounds off to 4.65.\r<BR>\n" );
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document.write( "If you would like to check this (and I would before I embarrass myself to the world by posting another wrong answer!!), you can use a calculator to calculate <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.3%5E%284.6478%29 ALIGN=MIDDLE  ALT=\"2.3%5E%284.6478%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Using the calculator value of x, it comes out to 48, so it checks!!\r<BR>\n" );
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document.write( "R^2 at SCC\r<BR>\n" );
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document.write( " </SPAN>\n" );
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