document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=164625>Question 164625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi please help me. Correct me if I'm wrong plz. The question is<BR>\n" );
document.write( "(6t^-7)/ (2t^9) <BR>\n" );
document.write( "is the answer 3t^-16 or 3t^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #121306 by </B><A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><B>KnightOwlTutor(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KnightOwlTutor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KnightOwlTutor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=121306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6t^-7)/ (2t^9)\r<BR>\n" );
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document.write( "(6t^-7)=(6/t^7)*(1/2t^9)=3t^-16 \r<BR>\n" );
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document.write( "You can divde 6 by 2 and get 3 and add the negative exponents together to get -16\r<BR>\n" );
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document.write( "3/t^7+t^9=3/t^16=3t^-16\r<BR>\n" );
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document.write( " </SPAN>\n" );
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