document.write( "Question 164602: Find a three digit number whose tens digit is 4 times the hundred’s digit and the unit’s digit is one more than the ten’s digit. The square of the sum of the digits is 72 more than the number? \n" ); document.write( "
Algebra.Com's Answer #121300 by Fombitz(32388)\"\" \"About 
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Let's call the hundreds' digit A, tens' digit B, and ones' digit C.
\n" ); document.write( "The number is ABC, or numerically A*100+B*10+C.
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\n" ); document.write( "\"tens digit is 4 times the hundred’s digit\"
\n" ); document.write( "1.\"B=4A\"
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\n" ); document.write( "\"unit’s digit is one more than the ten’s digit\"
\n" ); document.write( "2.\"C=1%2BB=1%2B4A\"
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\n" ); document.write( "\"square of the sum of the digits is 72 more than the number\"
\n" ); document.write( "3.\"A%5E2%2BB%5E2%2BC%5E2=A%2A100%2BB%2A10%2BC%2B72\"
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\n" ); document.write( "Use eqs.1 and 2 and substitute for B and C in eq. 3 and solve for A.
\n" ); document.write( "3.\"A%5E2%2BB%5E2%2BC%5E2=A%2A100%2BB%2A10%2BC%2B72\"
\n" ); document.write( "\"A%5E2%2B%284A%29%5E2%2B%281%2B4A%29%5E2=A%2A100%2B%284A%29%2A10%2B%281%2B4A%29%2B72\"
\n" ); document.write( "\"A%5E2%2B16A%5E2%2B1%2B8A%2B16A%5E2=100A%2B40A%2B1%2B4A%2B72\"
\n" ); document.write( "\"33A%5E2%2B8A%2B1=144A%2B73\"
\n" ); document.write( "\"33A%5E2-136A-72=0\"
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\n" ); document.write( "This quadratic equation does not have an integer solution.
\n" ); document.write( "Please check the problem set-up because something is wrong.
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\n" ); document.write( "The only possible number choices are 001, 145, and 289.
\n" ); document.write( "The \"sum of the squares\" for those are : 1, 42, 149.
\n" ); document.write( "While \"72 more than the number\" is: 73, 217, 361.
\n" ); document.write( "Clearly the last two lines aren't equal.
\n" ); document.write( "There is no solution the way the problem is set up.
\n" ); document.write( "Please check and re-post.
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