document.write( "Question 164607: Find a three digit number whose tens digit is 4 times the hundred’s digit and the unit’s digit is one more than the ten’s digit. The square of the sum of the digits is 72 more than the number? \n" ); document.write( "
Algebra.Com's Answer #121287 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! Let H be the hundred digit. \n" ); document.write( "Then the tens digit is 4H \n" ); document.write( "The ones digit is 4H+1\r \n" ); document.write( "\n" ); document.write( "The \"number is (H*100)+(4H*10)+(4H+1) = (100H)+(40H)+(4H+1)= 144H + 1 \n" ); document.write( "The sum of the digits is H+4H+4H+1 = 9H+1\r \n" ); document.write( "\n" ); document.write( "You are told the square of the sum of the digits is 72 more than the number itself \n" ); document.write( "So \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "H = -4/9 or 18/9=2 \n" ); document.write( "Since the number is an integer, the answer must be H=4\r \n" ); document.write( "\n" ); document.write( "Test your answer. Does |