document.write( "Question 23347: 2x^-2y^0(x^2y^0-4x^-6y^4 \n" ); document.write( "
Algebra.Com's Answer #12128 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
2x^-2y^0(x^2y^0-4x^-6y^4\r\n" );
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document.write( "Is this what you mean?\r\n" );
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document.write( "2x-2y0(x2y0 - 4x-6y4)\r\n" );
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document.write( "If so, replace both y0's by 1.\r\n" );
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document.write( "2x-2·1(x2·1 - 4x-6y4)\r\n" );
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document.write( "2x-2(x2 - 4x-6y4)\r\n" );
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document.write( "Now use the distributive principle:\r\n" );
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document.write( "2x-2·x2 - 8x-2·4x-6y4\r\n" );
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document.write( "Add the exponents of x in the first term: -2 + 2 = 0,\r\n" );
document.write( "so replace x-2·x2 by x0\r\n" );
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document.write( "2x0 - 8x-2·x-6y4\r\n" );
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document.write( "But x0 is just 1, so replace x0 by 1\r\n" );
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document.write( "2·1 - 8x-2x-6y4\r\n" );
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document.write( "2 - 8x-2x-6y4\r\n" );
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document.write( "Now add the exponents of x in the second term:\r\n" );
document.write( "-2 + -6 = -8. so replace x-2x-6 by x-8\r\n" );
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document.write( "2 - 8x-8y4\r\n" );
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document.write( "To get rid of the negative exponent in x-8, replace\r\n" );
document.write( "x-8 by 1/x8\r\n" );
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document.write( "2 - 8(1/x8)y4\r\n" );
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document.write( "Simplify the second term:\r\n" );
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document.write( "2 - 8y4/x8\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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